Respuesta :

kevinclq0811

Answer:

as following

Step-by-step explanation:

[tex](3y^3+5y^2-4y) (2y^2-6y-7) \\=y(3y^2+5y-4)(2y^2-6y-7)\\=y(6y^4-16y^3-21y^2+10y^3-30y^2-35y-8y^2+24y+28)\\=y(6y^4-6y^3-59y^2-11y+28)\\=6y^5-6y^4-59y^3-11y^2+28y[/tex]