Respuesta :
lets say we have a triangle ABC
if A is the biggest angle, the side oposite that angle (BC) will be the longest
so
perimiter=AB+BC+AC
P=30=5x-7+3x+1+4x
find x
30=5x-7+3x+1+4x
30=5x+3x+4x-7+1
30=12x-6
add 6
36=12x
divide 12
3=x
evaluate each
AB=5(3)-7=15-7=22
BC=3(3)+1=9+1=10
AC=4(3)=12
AB>AC>BC
the oposite one
C>B>A
smallest to largest
A<B<C
answer is option A
if A is the biggest angle, the side oposite that angle (BC) will be the longest
so
perimiter=AB+BC+AC
P=30=5x-7+3x+1+4x
find x
30=5x-7+3x+1+4x
30=5x+3x+4x-7+1
30=12x-6
add 6
36=12x
divide 12
3=x
evaluate each
AB=5(3)-7=15-7=22
BC=3(3)+1=9+1=10
AC=4(3)=12
AB>AC>BC
the oposite one
C>B>A
smallest to largest
A<B<C
answer is option A
Answer:
Option D is correct.
From smallest to largest the angles are; Angles C , A , B
Step-by-step explanation:
Perimeter of a triangle is the sum of all the sides.
Given: In triangle ABC, the perimeter is 30 feet and
AB = 5x -7 , BC = 3x+1 and AC =4x
By definition of perimeter;
Perimeter of triangle ABC = AB + BC + AC
Substitute given values we have;
[tex]30 = 5x -7 + 3x +1 +4x[/tex]
Combine like terms;
[tex]30 = 12x - 6[/tex]
Add 6 to both sides we get;
30 +6 = 12x -6 +6
Simplify:
36 = 12 x
Divide both sides by 12 we get;
3 = x
Side of AB = 5x -7 = 5(3) -7 = 15 -7 = 8 units.
Side of BC = 3x + 1 = 3(3) + 1 = 9 + 1 = 10 units.
and
Side of AC = 4x = 4(3) = 12 units.
[tex]AB < BC < AC[/tex]
As, the largest angle will be opposite 12 because it is the longest side. Similarly, the smallest angle will be opposite 8, which is the shortest side.
[tex]\angle C < \angle A < \angle B[/tex]