Respuesta :

umakantshahumakant2

Step-by-step explanation:

3-2log 10(2) -5 log 10(2y)

log 10 (10)3 -2 log 10 (2) -5 log 10 (2y)

3-2 log 10 (2) -5 log 10 (2y)

3+log 10 (2-^2) -5 log 10 (2y)

3+log 10 (2-^2)+ log 10 {(2y)-^5}

3+log 10 (2-^2 ×(2y)-5)

3+ log 10 (2^-2 × 2^-5 y^-5)

3+ log 10 (2^-2×2^-5 ×1/y^5

3+ log 10 (2^-7/y^5)- 3+ log 10 (1/y^5×2^7)

3+ log 10 (1/y^5×128)

3+log 10 (1/128 y^5)

3+log 10 {(128 y^5)^-1)

3- log 10 (128 y^5)

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