Answer:
[tex]29+\sqrt{5}[/tex]
Step-by-step explanation:
Let [tex]\sqrt{5} = a[/tex] for simplicity. now our equation is
(2a+1)(3a-1)
now expand
2a*3a-2a+3a-1 = 6a^2+a-1
remember that [tex]\sqrt{5} = a[/tex]
thus we get[tex]6\sqrt{5}^2+\sqrt{5}-1 = 6(5)-1+\sqrt{5}=30-1+\sqrt{5}=29+\sqrt{5}[/tex]
