Answer:
(1, 9)
Step-by-step explanation:
For quadratic ax^2 +bx +c, the vertex is located at ...
x = -b/(2a)
For your quadratic, this is ...
x = -(-6)/(2(3)) = 1
The y-value at that point is ...
y = 3(1^2) -6(1) +12 = 3 -6 +12 = 9
The vertex is (x, y) = (1, 9).
