Answer:
[tex]\frac{16t}{5} and \frac{1}{5}[/tex]
Step-by-step explanation:
[tex]\frac{1}{4}*\frac{5t-1}{4}=\frac{5t-1}{16}[/tex]
Inverse of [tex]\frac{5t-1}{16}[/tex] = [tex]\frac{16t}{5}+\frac{1}{5}[/tex]
Please leave a comment if I got anything wrong.
