h(x)=
⎩
⎪
⎪
⎪
⎪
⎪
⎪
⎪
⎪
⎨
⎪
⎪
⎪
⎪
⎪
⎪
⎪
⎪
⎧
​

x
3

x
24
​
−1
(x−1)(x+3)
​

,
,
,
​

x∈(−∞,0]
x∈(0,8]
x∈(8,∞)
​

h
(
−
3
)
=
h(−3)=h, left parenthesis, minus, 3, right parenthesis, equals