Answer:
5
Step-by-step explanation:
m∠DBC = m∠ACB
4[tex]x^{2}[/tex]-6=10x
4[tex]x^{2}[/tex]-10x-6=0
(4x-2)(x+3)=0
x = [tex]\frac{1}{2}[/tex] or -3
The angle can't be negative.
∴ x = [tex]\frac{1}{2}[/tex]
m∠ACB = 4[tex]x^{2}[/tex] = 10x = 10 X [tex]\frac{1}{2}[/tex]= 5
I hope it helps you!
