paulocean70 paulocean70
  • 05-03-2022
  • Physics
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need help with this question ​

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indrawboy
indrawboy indrawboy
  • 05-03-2022

[tex]\tt h=\dfrac{vo^2~sin^2\theta}{2g}\rightarrow \theta=90\\\\h=\dfrac{vo^2}{2g}=\dfrac{2.78^2}{2\times 9.8}=0.394~m[/tex]

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