The temperature of the given mole and pressure of gas is 300.6K.
Given the data in the question;
Temperature; [tex]T = \ ?[/tex]
The Ideal gas law or general gas equation emphasizes on the state or behavior of a hypothetical ideal gas. It states that pressure multiplied by volume is equal to moles multiply by the universal gas constant multiply by temperature. It is expressed;
[tex]PV = nRT[/tex]
Where P is pressure, V is volume, n is the amount of substance, T is temperature and R is the ideal gas constant ( [tex]0.08206Latm/molK[/tex] 0
The determine the temperature of the gas, we substitute our given values inro the equation above.
[tex]PV = nRT\\\\T = \frac{PV}{nR}\\ \\T = \frac{16.40atm\ *\ 18.35L }{12.20mol\ * \ 0.08206Latm/molK} \\\\T = \frac{300.94Latm}{1.001132molLatm/molK} \\\\T = 300.6K[/tex]
Therefore, the temperature of the given mole and pressure of gas is 300.6K.
Learn more about Ideal Gas Law: brainly.com/question/4147359
