An object that is initially not rotating has a constant torque of 3.6 Nâ‹…m applied to it. The object has a moment of inertia of 6 kgâ‹…m2.What is the magnitude of the angular acceleration of the object?
[Please answer if you know]
Angular acceleration is equal to Net Torque divided by rotational inertia, which is the rotational equivalent to Newton’s 2nd Law.  Therefore, angular acceleration is equal to 3.6/6 which is 0.6. Hope this helped!
