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Taking into account the reaction stoichiometry, 0.2066 grams of CO₂ are formed from 0.500 grams of iron oxide and an excess of carbon.

Reaction stoichiometry

In first place, the balanced reaction is:

2 Fe₂O₃ + 3 C → 4 Fe + 3 CO₂

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

  • Fe₂O₃: 2 moles
  • C: 3 moles
  • Fe:4 moles
  • CO₂: 3 moles

The molar mass of the compounds is:

  • Fe₂O₃: 159.7 g/mole
  • C: 12 g/mole
  • Fe: 55.85 g/mole
  • CO₂: 44 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

  • Fe₂O₃: 2 moles ×159.7 g/mole= 319.4 grams
  • C: 3 moles ×12 g/mole= 36 grams
  • Fe: 4 moles ×55.85 g/mole= 223.4 grams
  • CO₂: 3 moles ×44 g/mole= 132 grams

Mass of CO₂ formed

The following rule of three can be applied: if by reaction stoichiometry 319.4 grams of Fe₂O₃ form 132 grams of CO₂, 0.500 grams of Fe₂O₃ form how much mass of CO₂?

[tex]mass of CO_{2} =\frac{0.500 grams of Fe_{2}O_{3}x132 grams of CO_{2} }{319.4 grams of Fe_{2}O_{3}}[/tex]

mass of CO₂= 0.2066 grams

Then, 0.2066 grams of CO₂ are formed from 0.500 grams of iron oxide and an excess of carbon.

Learn more about the reaction stoichiometry:

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