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Line segment segment CD has a slope of negative start fraction two over three end fraction and contains point C(−3, −6). What is the y-coordinate of point Q(−1, y) if segment QC is perpendicular to line segment segment CD question mark
y = 3
y = 0
y = −2
y = −3

Respuesta :

For perpendicular lines, the slopes are negative reciprocals of one another. Therefore, the slope of QC = 3/2

Using this into the formula of slope:
3/2 = (y + 6) / (-1 + 3)
y = -9

If the slope of CD is 2/3, then y works out to be -3.