Respuesta :

bunnuika

goal:tan^5x=tanx(sec²x-2sec²x+1)

proof: from l.h.s to r.h.s

tan^5x=(tanx)^5=((tanx)(tan²x)(tan²x))

from trigonometry identity

(tan²x)=sec²x-1

tan^5x=(tanx(sec²x-1)(sec²x-1))

=(tanx(sec^4x-sec²x-sec²x+1))

=(tanx(sec^4x-2sec²x+1))

proved