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A ball is thrown up on the surface of a moon. It’s height above the lunar surface (in feet) after ‘t’ seconds is given by the formula

h =592t - 16/7t^2

Find the time that the ball reaches its maximum height.

A ball is thrown up on the surface of a moon Its height above the lunar surface in feet after t seconds is given by the formula h 592t 167t2 Find the time that class=

Respuesta :

reinhard10158

Step-by-step explanation:

we get the points with extreme values as the 0 points of the first derivative of the function.

h'(t) = 592 - 32/7 t = 0

592 = 32/7 t

4144 = 32t

t = 129.5 seconds

so, it will reach its max. height after 129.5 seconds.

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