SOLUTION
Write out the expression
[tex]i^{22}[/tex][tex]\begin{gathered} i^{22} \\ \text{can be written as} \\ (i^2)^{11} \end{gathered}[/tex]
Recall that
[tex]i^2=-1[/tex]
Replace into the expression above
[tex](-1)^{11}=-1[/tex]
Hence
[tex]i^{22}=-1[/tex]
Therefore
The first option is Right
