N 2.06
we have the function
[tex]H(x)=-2\sqrt[3]{x}+1[/tex]
For each value of x, substitute in the given function to obtain the value of H(x)
so
For x=-8
substitute
[tex]\begin{gathered} H(x)=-2\sqrt[3]{-8}+1 \\ H(x)=-2(-2)+1 \\ H(x)=5 \end{gathered}[/tex]
For x=0
[tex]\begin{gathered} H(x)=-2\sqrt[3]{0}+1 \\ H(x)=-2(0)+1 \\ H(x)=1 \end{gathered}[/tex]
For x=1
[tex]\begin{gathered} H(x)=-2\sqrt[3]{1}+1 \\ H(x)=-2(1)+1 \\ H(x)=-1 \end{gathered}[/tex]
