Given:
A = 37.2°
b = 10.1 in
c = 6.2 in
Let's find the area of the traingle.
To find the area, apply the formula below:
[tex]\text{Area}=\frac{1}{2}\ast b\ast c\ast\sin A[/tex]Hence, we have:
[tex]Area=\frac{1}{2}\ast10.1\ast6.2\ast\sin 37.2[/tex]Solving further:
[tex]\begin{gathered} \text{Area}=\frac{1}{2}\ast10.1\ast6.2\ast0.605 \\ \\ \text{Area}=18.9\text{ }\approx19in^2 \end{gathered}[/tex]Therefore, the area of triangle ABC is 19 square inches
ANSWER:
A. 19 in²
