Solve the equation system
3x+2y=16 (I)
5x+y=9 (II)
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By the substitution method
5x+y=9
y= 9 -5x
Replacing y in (I)
3x + 2(9-5x) = 16
3x + 18 - 10x = 16
(3-10) x= 16 -18
7x = 2
x= 2/7
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y= 9 -5x
y = 9 - 2* (2/7)
y= 9 - 4/7
y = (63-4) / 7
y = 59/ 7
