The expression is given
[tex]4^2\times^{}\frac{4^3}{4^{-4}}^{}[/tex]
Solving the expression using the bodmas rule.
[tex]4^2\times4^{3+4}=4^2\times4^7[/tex]
Since the expression is in multiplication having same base then the power is added.
[tex]4^{2+7}=4^9[/tex]
Hence the base is 4 and exponent is 9.
The answer is
[tex]4^9[/tex]
