To find x, we have to use Pythagorean's Theorem.
[tex](hip)^2=(leg_1)^2+(leg_2)^2[/tex]
Let's replace each of them.
[tex]x^2=4^2+6^2[/tex]
Let's solve for x.
[tex]\begin{gathered} x=\sqrt[]{16+36} \\ x=\sqrt[]{52}\approx7.2 \end{gathered}[/tex]
Therefore, x is 7.2, approximately.
