Given:
[tex]p(x)=x^3-6x^2-5x-14[/tex]
Factor of (x-7) is:
[tex]\begin{gathered} =\frac{p(x)}{x-7} \\ =\frac{x^3-6x^2-5x-14}{x-7} \end{gathered}[/tex]
so factor of (x-7) is:
[tex]\begin{gathered} p(x)=x^3-6x^2-5x-14 \\ =(x-7)(x^2+x+2) \end{gathered}[/tex]
