Answer: ( -8, 47 )
Given:
[tex]\begin{cases}0.6x+0.2y=4.6 \\ 1.5x+0.3y=2.1\end{cases}[/tex]
First, let us multiply equation 1 by 3, and equation 2 by -2. We will now get:
[tex]\begin{cases}1.8x+0.6y=13.8 \\ -3x-0.6y=-4.2\end{cases}[/tex]
Add the two equations and we will get:
[tex]-1.2x=9.6[/tex]
*Divide both sides by -1.2
[tex]x=\frac{9.6}{-1.2}=-8[/tex]
Now, going back to the equations, we can choose any of the two to find the value of y.
Using equation 1:
[tex]0.6x+0.2y=4.6[/tex][tex]0.6(-8)+0.2y=4.6[/tex][tex]0.2y=4.6+4.8[/tex][tex]0.2y=9.4[/tex]
*Divide both sides by 0.2
[tex]y=\frac{9.4}{0.2}=47[/tex]
Therefore, the solution to this system of equation is ( -8, 47 )
