Answer:
Concentration of 1.798 M of the potassium ion.
Explanation:
1st) It is necessary to write the dissociation equation of K2CO3:
[tex]K_2CO_3\rightarrow2K^++CO_3^{-2}[/tex]2nd) In the dissociation equation of K2CO3, we can see that from 1 mole of K2CO3, 2 moles of potassium ion (K+) are formed, so from 0.899 M K2CO3 solution we will have:
2 x 0.899M = 1.798 M
a concentration of 1.798 M of the potassium ion.
