ANSWER
a = 12.5 m/s²
EXPLANATION
Given:
• The radius of the circular path, r = 2 m
,• The speed of the object, v = 5 m/s
Find:
• The centripetal acceleration of the object, a.
The centripetal acceleration of an object moving at a speed v in a circular path of radius r is,
[tex]a=\frac{v^2}{r}[/tex]Replace the known values and solve,
[tex]a=\frac{5^2m^2/s^2}{2m}=\frac{25}{2}m/s^2=12.5m/s^2[/tex]Hence, the acceleration of the object is 12.5 m/s².
