[tex]\begin{gathered} \text{ 3x + 4y = 12} \\ \text{ 4y = -3x + 12} \\ \text{ y = -}\frac{3}{4}x\text{ + }\frac{12}{4} \\ \text{ y = -}\frac{3}{4}x\text{ + 3} \end{gathered}[/tex]
slope = -3/4
y-intercept = 3
THe first choice is the correct answer to your question
