Explanation
The equivalent capacitance of two capacitors connected in parallel is the sum of the individual capacitances.
[tex]C_{eq}=C_1+C_2[/tex]Step 1
Let
[tex]\begin{gathered} C_1=4\mu F \\ C_2=8\mu F \end{gathered}[/tex]hence
[tex]\begin{gathered} C_{eq}=C_1+C_2 \\ C_{eq}=4\mu F+8\mu F \\ C_{eq}=12\mu F \end{gathered}[/tex]therefore, the answer is
[tex]12\mu F[/tex]I hope this helps you
