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How much heat will be absorbed when 38.2g of Bromine reacts with excess H2 according to the following equation?H2 + Br2 --> 2HBr ∆H° = 72.80kJ

Respuesta :

Explanation:

First, let's transform 38.2 grams of Br2 into moles using is molar mass (MM of Br2 = 159.808 g/mol)

159.808 g --- 1 mol

38.2 g ---- x

x = 0.239 moles

Now, let's calculate how much heat will be absorbed:

72.80kJ --- 1 mol

x --- 0.239 moles

x = 17.4 kJ

Answer: 17.4 kJ