We have to use the volume formula for a cone.
[tex]V=\frac{1}{3}B\cdot h[/tex]Where B is the base area
[tex]\begin{gathered} B=\pi(r)^2=3.14(6)^2 \\ B\approx113.04 \end{gathered}[/tex]Now, we can find the volume
[tex]V=\frac{1}{3}\cdot113.04\cdot12=452.16u^3[/tex]