I solved this and think the answer is all real numbers except 3. Can you confirm if I solved this correctly? Thanks!
All real numbers except 3
The domain of a function are the independent values of the function for which it exists.
Given the function expressed as:
[tex]f(x)=\frac{13}{3-x}[/tex]A rational function does not exist if the denominator is zero. For the given function, it tends to infinity when 3 - x = 0
3 - x = 0
x = 3
This shows that the function exists on all real number except 3. The domain of the function in interval form is expressed as:
[tex]Domain:(-\infty,3)U(3,\infty)[/tex]