SOLUTION:
Step 1:
In this question, we are given the following:
Step 2:
Let the distance from Amelia to the top of the tower be h,
such that:
[tex]\begin{gathered} \sin 30^0=\frac{50ft}{h} \\ h\text{ = }\frac{50ft}{\sin 30^0} \\ h\text{ = }\frac{50ft}{0.5} \\ h\text{ = 100ft} \end{gathered}[/tex]
CONCLUSION:
The distance from Amelia to the top of the tower = 100ft
