Given 3√72:
First, we decompose 72 into its prime factors, as follows:
72 = 2 x 2 x 2 x 3 x 3
So, we can rewrite the root as:
[tex]3\sqrt[]{2\times2^2\times3^2}=[/tex][tex]\begin{gathered} 3\text{ x 2 x 3}\sqrt[]{2} \\ =\text{ 18}\sqrt[]{2} \end{gathered}[/tex]
