We are asked to solve the given summation problem.
The summation problem says to add (4i + 5) for i = 1 to 6.
[tex]For\;i=1:\;\;(4*1+5)=4+5=9[/tex][tex]For\;i=2:\;\;(4*2+5)=8+5=13[/tex][tex]For\;i=3:\;(4*3+5)=12+5=17[/tex][tex]For\;i=4:\;\;(4*4+5)=16+5=21[/tex][tex]For\;i=5:\;(4*5+5)=20+5=25[/tex][tex]For\;i=6:\;\;(4*6+5)=24+5=29[/tex]
Finally, now add them all together.
[tex]9+13+17+21+25+29=64[/tex]
Therefore, the given summation problem is equal to 64
