The area of the circle is equal to
[tex]A=\pi\cdot r^2[/tex]we have
pi=3.14
D=8 in
r=D/2=8/2=4 in -----> the radius is half the diameter
substitute given values in the formula
[tex]\begin{gathered} A=3.14\cdot4^2 \\ A=50.24 \end{gathered}[/tex]therefore
