Answer:
The zeros are rational numbers
Explanation:
When we have an equation of the form
f(x) = ax² + bx + c
The zeros of the function are rational if b² - 4ac ≥ 0 and irrational if b² - 4ac < 0
In this case, we have the equation
f(x) = 4x² + 7x + c
Where c = 3, so the equation is
f(x) = 4x² + 7x + 3
Now, a = 4, b = 7, and c = 3, so the term b² - 4ac is equal to:
b² - 4ac = 7² - 4(4)(3)
b² - 4ac = 49 - 48
b² - 4ac = 1
Since 1 is greater than 0, we can say that the zeros are rational numbers.
