[tex]\begin{gathered} y=3(x+2)^2\text{ - 8} \\ \end{gathered}[/tex]
From the general equation of a parabola
[tex]y=a(x-h)^2\text{ + k}[/tex]
a = 3
The parabola will open up because it is positive.
The parabola has a minimum
The axis of symmetry is at x = -2
Vertex = (-2, -8)
y - intercept (0, 4)
The equation of the graph
y = 3 (x+2)(x+2) - 8
= 3( x^2 +4x +4) - 8
= 3x^2 +12x+12-8
y= 3x^2 +12x +4
