If the hypotenuse of this triangle 30º 60º 90º is 20, let me draw it:
The longer leg is the opposite side to the wider angle measure. So to calculate it we need this formula:
[tex]\begin{gathered} \sin (60)=\frac{opposite\text{ side}}{\text{hypotenuse}}=\frac{x}{20} \\ \frac{\sqrt{3}}{2}=\frac{x}{20} \\ 2x=20\sqrt{3} \\ \frac{2x}{2}=\frac{20\sqrt{3}}{2} \\ x=10\sqrt{3} \end{gathered}[/tex]
Since the sine of 60º is the square root of 3/2 then we have this ratio,
therefore the answer is
x=10√3
