LilanaP476003 LilanaP476003
  • 04-11-2022
  • Mathematics
contestada

(2 to the square root of x+2) times (square root of x+3)

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NadimI729941 NadimI729941
  • 04-11-2022

The given expression is:

[tex]2\sqrt{x+2}\times\sqrt{x+3}[/tex]

To evaluate the given expression, we apply the rule:

[tex]\begin{gathered} \sqrt{a}\times\sqrt{b}=\sqrt{ab} \\ 2=\sqrt{4} \end{gathered}[/tex]

Therefore:

[tex]\begin{gathered} 2\sqrt{x+2}\times\sqrt{x+3} \\ =\sqrt{4(x+2)(x+3)} \\ =\sqrt{4(x^2+2x+3x+6)} \\ =\sqrt{4(x^2+5x+6)} \\ =\sqrt{4x^2+20x+24} \end{gathered}[/tex]

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