Given:
[tex](x+y)^2-37[/tex]To find: Evalute if x =4 and y = -9?
Solution:
We have given that
[tex]=(x+y)^2-37\ldots\text{.}\mathrm{}(1)[/tex]Here, we use the identity
[tex](a+b)^2=a^2+2ab+b^2[/tex]Eq.1 becomes
[tex]=x^2+2xy+y^2-37[/tex]Now, substitute x = 4 and y = -9
We get,
[tex]\begin{gathered} =(4)^2+2(4)(-9)+(-9)^2-37 \\ \\ =16-72+81-37 \\ \\ =81+16-37-72 \\ \\ =97-109 \\ \\ =-12 \end{gathered}[/tex]Hence, (x+y)^2 -37 = -12 if x =4 and y = -9
Thus, (x+y)^2 -37 = -12 if x = 4 and y = -9.
