Given data
The speed of the rocket is v = 32.5 m/s
The angle of projection of the rocket is theta = 28.8 degree
The expression for the distance of the log on the flat ground is given as:
[tex]R=\frac{v^2\sin 2\theta}{g}[/tex]
Substitute the value in the above equation.
[tex]\begin{gathered} R=\frac{(32.5\text{ m/s})^2\times\sin (2\times28.8\circ)}{9.8m/s^2} \\ R=91\text{ m} \end{gathered}[/tex]
Thus, the distance of the log on the flat ground is 91 m.
