Answer:
-2 and -4
Explanation:
Given the function g(x)=x^2+6x+8, tthe zero of the function is at f(x) = 0
Substitute
x^2+6x+8 = 0
Factorize
x^2+4x+2x+8 = 0
x(x+4)+2(x+4) =0
(x+2)(x+4) = 0
x+2 = 0 and x+4 = 0
x = -2 and -4
Hence the zeros of the function are -2 and -4
