The given equation is
[tex]x^2-4x+1=-3[/tex]First, we have to move the term -3
[tex]\begin{gathered} x^2-4x+1+3=0 \\ x^2-4x+4=0 \end{gathered}[/tex]Where a = 1, b = -4, and c = 4.
The discriminant formula is
[tex]D=b^2-4ac[/tex]Replacing the values, we have
[tex]D=(-4)^2-4(1)(4)=16-16=0[/tex]The discriminant is zero.Given that the discriminant is zero, it means the equation has a unique solution.
