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The length of a rectangle is five less than twice the width. The perimeter of the rectangle is 110. Find the dimensions of the rectangle. 22. Let L represent the length and W represent the width. Write a system of equations.(only need help with 22 )

The length of a rectangle is five less than twice the width The perimeter of the rectangle is 110 Find the dimensions of the rectangle 22 Let L represent the le class=

Respuesta :

Step 1

Let width = w

Length = 2w - 5

2L + 2w = 110

Perimeter of a rectangle = 2Length = 2Width

110 = 2(2w - 5) + 2(w)

110 = 4w - 10 + 2w

110 + 10= 4w + 2w

120 = 6w

w = 120/6

w = 20

width = 20

Length = 2(20) - 5

= 40 - 5

= 35

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