Answer: y = -3x + 1
Slope-point form:
[tex]y+5=-3(x-2)[/tex]Let us simplify the equation to form the slope-intercept form of the equation of the line.
[tex]\begin{gathered} y+5=-3(x-2) \\ y+5=-3x+6 \\ y=-3x+6-5 \\ y=-3x+1 \end{gathered}[/tex]Therefore, its slope-intercept form is y = -3x + 1.