Given the quadratic equation below
[tex]x^2+6x-5=0[/tex]
Using the method of completing the square we have that:
[tex]\begin{gathered} (x^2+6x)-5=0 \\ (x+3)^2-9-5=0 \\ (x+3)^2-14=0 \end{gathered}[/tex][tex]\begin{gathered} (x+3)^2=14 \\ (x+3)=\pm\sqrt[]{14} \\ x=-3\pm\sqrt[]{14} \end{gathered}[/tex]
Hence, from the above solution, the value of m is -3 and n is √14
