Answer:
Concept:
The opposite angles of a cyclic quadilateral are supplementary
[tex]\begin{gathered} \angle A+\angle C=180^0 \\ \angle C=89^0 \end{gathered}[/tex]
By applying the principle, we will have
[tex]\begin{gathered} \angle A+\angle C=180^0 \\ \angle A+89^0=180^0 \\ \angle A=180^0-89^0 \\ \angle A=91^0 \end{gathered}[/tex]
Hence,
The final answer for ∠A =91°
The SECOND OPTION is the right answer
