We are given the following two points
[tex]R(-5,8)\quad and\quad T(3,14)[/tex]Recall that the midpoint formula is given by
[tex]RT=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})[/tex]Let us substitute the given coordinates into the above midpoint formula
[tex]\begin{gathered} RT=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}) \\ RT=(\frac{-5_{}+3}{2},\frac{8_{}+14}{2}) \\ RT=(\frac{-2}{2},\frac{22}{2}) \\ RT=(-1,11) \end{gathered}[/tex]Therefore, the point (-1, 11) is the midpoint of RT.
Option (3) is the correct answer.
