Given:
4x² - 27 + 18
4x² - 9
Applying the difference of two squares.
(2x - 3)(2x + 3)
To solve for x-intercept;
(2x - 3)(2x + 3) = 0
Either 2x-3= 0 or 2x+3=0
2x = 3 ⇒ x = 3/2 or 2x = -3 ⇒ x = -3/2
There are two x-intercepts and they are: (3/2 , 0 ) and (-3/2 , 0)
