Given data:
* The mass of the dart is m = 0.025 kg.
* The speed of the dart is v = 13 m/s.
Solution:
(a). The work done by the dartboard to stop the dart is,
[tex]W=\frac{1}{2}mv^2[/tex]
Substituting the known values,
[tex]\begin{gathered} W=\frac{1}{2}\times0.025\times13^2 \\ W=2.1125\text{ J} \end{gathered}[/tex]
Thus, the amount of work done by the dartboard is 2.1125 J.
(b). As the friction of dartboard
