a = 1, b = 6, c = -1
Using the quadratic formula:
[tex]x\text{ = }\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}=\frac{-6\pm\sqrt[]{6^2-4\cdot1\cdot(-2)_{}}}{2\cdot1}=\frac{-6\pm\sqrt[]{36+8}}{2}=\frac{-6\pm\sqrt[]{44}}{2}=\frac{-6\pm6.6332}{2}[/tex][tex]x_1=\frac{-6+6.6332}{2}=\frac{0.6332}{2}=0.3166[/tex][tex]x_2=\frac{-6-6.6332}{2}_{}_{}=\frac{-12.6332}{2}=-6.3166[/tex]Answer:
x1 = 0.3166
x2 = -6.3166
